The solution of the differential equation (1+y^2) + (x-e^{\tan^{-1}y \frac{dy}{dx}}) = 0 , is

Correct Answer is : 2xetan−1y = e2tan−1y + K

2xe^{\tan^{-1}y} = e^2tan^{-1} y + K

xe 2 \tan^{-1} y = etan^{-1} y + K

VITEEE 2013 Paper

Section: Mathematics

Question : 119 of 120

Marks: +1, -0

The solution of the differential equation
(1+y2) + (x−etan−1y

) = 0 , is

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