VITEEE 2013 Paper

x + 2 ≥ , i.e. x ≥ - 2 or - 2 ≤ x
log10 (1 - x) ≠ 0
⇒ 1 - x ≠ 1 ⇒ x ≠ 0
Again , 1 - x > 0
⇒ 1 > x ⇒ x < 1
Combining all the results for values of x, we get
-2 ≤ x < 0 and 0 < x < 1