If the gradient of the tangent at any point (x, y) of a curve which passes through the point (1,\pi/4) is \{y/x - \sin^2 (y/x)\} , then equation of the curve is

Correct Answer is : y = x cot−1 (loge ex)

VITEEE 2013 Paper

Section: Mathematics

Question : 120 of 120

Marks: +1, -0

If the gradient of the tangent at any point (x, y) of a curve which passes through the point (1,

) is {

−sin2(

)} , then equation of the curve is

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