TS ICET 24 May 2019 Shift 1 Paper

Question : 138 of 200

Marks: +1, -0

Let P be an external point to a circle and PT be a tangent drawn from P meeting the circle at T. If AB is a chord of the circle such that A, B, P are collinear. PT = 5 cm and PB = 4 cm then PA =

6 cm
6.25 cm
6.5 cm
6.75 cm

Validate

Solution:

We know that,

PA . PB = PT^2

P A=\;{(5)^{2}}/{4}=\;{25}/{4}=6.25

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