TS ICET 24 May 2018 Shift 1 Paper

Question : 130 of 200

Marks: +1, -0

The coefficient of

\x^7

in the binomial expansion of

(2\x^3+1/{4\x^2})^9

Solution:

Let

T_{r+1}

be the term that contain

x^7

r=\;{n p-k}/{p+q}=\;{9 × 3-7}/{3+2}=\;{20}/{5}=4

∴ coefficient of

T_{5}=T_{4+1}=9_{C 4}(2)^{9-4}(\;{1}/{4})^{4}

=126 × \;{2^{5}}/{2^{8}}

=\;{126}/{8}=\;{63}/{4}

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