(1+\sqrt2)^4 + (1-\sqrt2)^4 =

TS ICET 24 May 2018 Shift 1 Paper

Question : 131 of 200

Marks: +1, -0

(1+√2)^4 + (1-√2)^4

Solution:

(√{2}+1)^{4}+(√{2}-1)^{4}

=2(^{4} C _{0}(√{2})^{4}+^{4} C _{2}(√{2})^{2}+^{4} C _{4})

=2(4+12+1)=34

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