TS ICET 24 May 2018 Shift 1 Paper

Question : 121 of 200

Marks: +1, -0

The angle of elevation o f the top of a pole from a point 100 m away from its foot is 60°. The height of the pole (in meters) is?

Solution:

Let AB be the pole
In ΔCAB

\tan 60^{∘}=\;{ AB }/{ AC }

√{3}=\;{ AB }/{100} ⇒ AB =100 √{3} m

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