If 0 is an acute angle, and tanθ = 1/\sqrt7 then, \frac{\sec^2\\theta +\tan^2\\theta}{\cosec^21\\theta+\cot^2\\theta} =

TS ICET 24 May 2018 Shift 1 Paper

Question : 120 of 200

Marks: +1, -0

If 0 is an acute angle, and tanθ =

1/√7

then,

{\sec^2\θ +tan^2\θ}/{\cosec^21\θ+\cot^2\θ}

Solution:

\;{\sec ^{2} θ+\tan ^{2} θ}/{cosec^{2} θ+\cot ^{2} θ}=\;{1+\tan ^{2} θ+\tan ^{2} θ}/{1+\cot ^{2} θ+\cot ^{2} θ}

=\;{1+{1}/{7}+{1}/{7}}/{1+7+7}=\;{9}/{7} × \;{1}/{15}=\;{3}/{35}

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