TS ICET 24 May 2018 Shift 1 Paper

Question : 122 of 200

Marks: +1, -0

a + b + c = 6;

a^2 + b^2 + c^2 = 26

⇒ ab + bc — ca = ?

Solution:

We know

(a+b+c)^{2}=a^{2}+b^{2}+c^{2}+2(a b+b c+c a)

(6)^{2}=26+2(a b+b c+c a)

=2(a b+b c+c a)=36-26

a b+b c+c a=5

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