TS ICET 23 May 2018 Shift 1 Paper

© examsiri.com

Question : 132 of 200

Marks: +1, -0

If A=

(\table\0,0,1;0,1,0;1,0,0)

and B =

(\table\1,0,0;0,1,0;0,0,1)

then

\A^{15}\B^{17}

+

\A^{17}\B^{15}

=

2A
2B
A+B
2(A+B)

Solution:

Given A=

(\table\0,0,1;0,1,0;1,0,0)

and B =

(\table\1,0,0;0,1,0;0,0,1)

A×B=(\table0+0+0,0+0+0,0+0+1;0+0+0,0+1+0,0+0+0;1+0+0,0+0+0,0+0+0)=A

A × A = A and B × B = B

A^n=A

and

B^n=B

Hence

A^15B^17+A^17B^15=AB+AB=2AB=2A

© examsiri.com

Go to Question:

Prev Question

Next Question