(1+\sqrt3)^6 + (1-\sqrt3)^6 =

TS ICET 23 May 2018 Shift 1 Paper

Question : 131 of 200

Marks: +1, -0

(1+√3)^6 + (1-√3)^6

Solution:

(1+√{3})^{6}+(1-√{3})^{6}=2[^{6} C _{0}+^{6} C _{2}(3)+^{6}C _{4}(9)+^{6} C _{6}(27)]

⇒(1+√3)^6+(1-√3)^6=416

Go to Question:

Prev Question

Next Question