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Question : 58 of 160
Marks:
+1,
-0
Solution:
P(a‌cos‌θ,bsin‌θ)and
Q(a‌cos(‌+θ),bsin‌(‌+θ))satisfy
‌+‌=1∴‌cos2θ+‌sin‌2θ=1 and
‌sin‌2θ+‌cos2θ=1∴ Adding both equations, we get
‌(cos2θ+sin‌2θ)+‌(sin‌2θ+cos2θ)=2 ⇒‌+‌=2⇒a2β2+b2α2=2α2β2 ∴‌‌‌(a2β2+b2α2)=α2β2
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