The axis of a parabola is along the line y=x and the distance of its vertex A from (0,0) is \sqrt{2} and that of its focus {S} from (0,0) is 2 \sqrt{2}. If {A} and {S} lie in first quadrant, then the equation of the parabola in parametric form is

Correct Answer is : x=(t+1)2,y=(t−1)2

x=(t-\sqrt{2})^{2}, y=(t+\sqrt{2})^{2}

TS EAMCET 18-July-2022 Shift 2 Solved Paper

Section: Mathematics

Question : 57 of 160

Marks: +1, -0

The axis of a parabola is along the line y=x and the distance of its vertex A from (0,0) is √2 and that of its focus S from (0,0) is 2√2. If A and S lie in first quadrant, then the equation of the parabola in parametric form is

x=(t+1)2,y=(t−1)2
x=t2,y=2t
x=(t−√2)2,y=(t+√2)2
x=t2+5,y=t2−5

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