© examsiri.com
Question : 59 of 160
Marks:
+1,
-0
Solution:
If
S≡(ae,0) , then
tan‌⋅tan‌=‌ If
S≡(−ae,0) , then
tan‌⋅tan‌=‌ ⇒|‌|<1 and
|‌|>1 According to the question,
‌tan‌⋅tan‌=−(2√2+3) ⇒|tan‌⋅tan‌|=2√2+3>1 ⇒‌=−(2√2+3)⇒e=‌ In this case,
S≡(−ae,0) i.e.
S≡(‌,0)
© examsiri.com
Go to Question: