TS EAMCET 14-Sep-2020 Shift 2 Solved Paper

Given, mass of object, m2=2kg
Velocity, v=(8t

⋀

i

+3t2

⋀

j

)m∕s
∴ Acceleration of object is given as
a=‌

dv

dt

=‌

d

dt

(8t

⋀

i

+3t2

⋀

j

)
a=8

⋀

i

+6t

⋀

j

ms−2
Hence,according to Newton's second law of motion, force on the object,
F=ma=2(8

⋀

i

+6t

⋀

j

)
⇒F=16

⋀

i

+12t

⋀

j

|F|=√162+(12t)2
⇒20=√162+(12f)2‌‌[‌ Given, ‌|F|=20N]
⇒‌‌400=256+144t2
⇒‌‌144t2=144⇒t2=1⇒t=1s
Put t=1 s in Eq. (i),we get
F=16

⋀

i

+12

⋀

j

∴ Angle made by force Frelativeto positive direction of X -axis is given asθ=tan−1(‌

FY

FX

)=tan−1(‌

12

16

)=tan−1(‌

3

4

)