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Question : 86 of 160
Marks:
+1,
-0
Solution:
Given that,
A1+A2=5A3 A1−A2=3A3 On adding Eqs. (i) and (ii), we get
2A1‌‌=8A3⇒A1=4A3 A1‌‌=4(2+4)[∵A3=2+4(‌ given ‌)] A1‌‌=8+16 On subtracting Eqs. (ii) from (i), we get
2A2=2A3⇒A2=A3=2+4 ‌‌‌=‌=‌ ‌‌=‌=‌=√16=4
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