TS EAMCET 14-Sep-2020 Shift 2 Solved Paper

All forces are resolved in two perpendicular axes (X and Y) as shown in the figure.Since, block of mass m is in equilibrium.
Hence, resolving the forces in x -direction, we get
|F2|‌cos(60∘)=|F1|cos(30∘)
|F2|×‌

1

2

=10×‌

√3

2

‌‌(∵|F1|=10N‌ given ‌)
|F2|=10√3N
Again, resolving the force in y -direction, we get
|F3|‌‌=|F1|sin(30∘)+|F2|sin(60∘)
‌‌=10×‌

1

2

+10√3×‌

√3

2

‌‌=5+15=20N