TS EAMCET 03 May 2019 Shift 2 Solved Paper

The given circle is
5x2−xy−5x+y‌‌=0
(x−1)(5x−y)‌‌=0
Therefore the centre of the circle is (1,5)
The second circle is given by
x2+y2−2x+2y−7‌‌=0
(x−1)2+(y+1)2‌‌=9
The centre of the circle is (1,-1) and radius is 3
Therefore, the equation of the first circle is
(x−1)2+(y−5)2=9
x2+y2−2x−10y+17=0
The equation of chord at (1,-1) is
x−y−2‌

(x+1)

2

−10‌

(y−1)

2

+17=0
2y−7=0