TS EAMCET 03 May 2019 Shift 2 Solved Paper

The point of intersection of lines is represented by
2x2−13xy−7y2+x+23y−6=0
Here, a=2,b=−7,c=−6
h=‌

−13

2

,g=‌

1

2

,f=‌

23

2

Points of intersection of line are given by the expression.

If the point (‌

bg−fh

h2−ab

,‌

af−gh

h2−ab

)=(‌

19

15

,‌

7

15

)
(x,y) divides the line

OA in the ration k:1 then
x=‌

‌ 19 15 k

k+1

,y=‌

‌ 7 15 k

k+1

since, (x,y) lie on the line x+y−1=0. Then

‌

19

15

k+‌

7

15

k‌‌=k+1
k‌‌=‌

15

11