SSC MTS 2 Aug 2019 Shift 1 Paper

Follow BODMAS rule to solve this question, as per the order is given below:
Step-1: Parts of an equation enclosed in ‘Brackets’ must be solved first and in the bracket,
Step-2: Any mathematical ‘Of’ or ‘Exponent’ must be solved next,
Step-3: Next, the parts of the equation that contains ‘Division’ and ‘Multiplication’ are calculated,
Step-4: Last but not least, the parts of the equation that contain ‘Addition’ and ‘Subtraction’ should be calculated.
Given expression is,
⇒ $\frac{72÷9+3-6-\left(2\times 3\right)+5\mathrm{of}3-\left(1+5\times 2-2\right)}{8÷4+2-\left(6\times 8÷2\right)+\left(7\times 4-2\times 2\right)}$ = ?
⇒ ? = $\frac{72÷9+3-6-6+5\mathrm{of}3-\left(1+10-2\right)}{8÷4+2-\left(6\times \frac{8}{2}\right)+\left(28-4\right)}$
⇒ $?=\frac{\frac{72}{9}+3-6-6+15-9}{\frac{8}{4}+2-24+24}$
⇒ $?=\frac{8+3-12+6}{2+2}$
⇒ ? = 5/4