SSC MTS 2 Aug 2019 Shift 1 Paper

Follow BODMAS rule to solve this question, as per the order is given below:
Step-1: Parts of an equation enclosed in ‘Brackets’ must be solved first and in the bracket,
Step-2: Any mathematical ‘Of’ or ‘Exponent’ must be solved next,
Step-3: Next, the parts of the equation that contains ‘Division’ and ‘Multiplication’ are calculated,
Step-4: Last but not least, the parts of the equation that contain ‘Addition’ and ‘Subtraction’ should be calculated.
Given expression is,
32 ÷ 4 of 2 × 3 + [5 of 6 − {7 of 8 (10 + 6 of $\frac{5}{6}$ ÷ 5 − 1 )÷ 80}] − 7 × 3 ÷ 2 = ?
⇒ ? = 32 ÷ 4 of 2 × 3 + [5 of 6 − {7 of 8 (10 + 6 $\times \frac{5}{6}\times \frac{1}{5}$ − 1) ÷ 80}] − 7 × 3 ÷ 2
⇒ ? = 32 ÷ 4 of 2 × 3 + [5 of 6 − {7 of 8 (10 + 1 − 1) ÷ 80}] − 7 × 3 ÷ 2
⇒ ? = 32 ÷ 4 of 2 × 3 + [5 of 6 − {7 of 8 × 10÷ 80}] − 7 × 3 ÷ 2
⇒ ? = 32 ÷ 4 of 2 × 3 + [5 of 6 − 7] − 7 × 3 ÷ 2
⇒ ? = 32 ÷ 4 of 2 × 3 + [23] − 7 × 3 ÷ 2
⇒ ? = 32 ÷ (4 × 2) × 3 + 23 − 7 × 3 ÷ 2
⇒ ? = $\frac{32}{8}\times$ 3 + 23 − 7 × $\frac{3}{2}$
⇒ ? = 12 + 23 – 10.5
= 35 – 10.5
= 24.5