SSC CPO SI and ASI Model Paper 9

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Question : 135 of 200

Marks: +1, -0

If tanθ = 1 then

{8 cos θ +5 sinθ}/ {cos ^3θ-2 sin^3 θ +7 sin θ}

is equal to

$13/ 8$
$11/ 6$
2
–1

Solution:

tanθ = 1 = tan45°
⇒θ = 45°

∴{8 cosθ +5 sinθ}/{cos^3 θ -2sin^3 θ +7 sinθ}

={8/√2+5/√2}/[1/ √2]^3-2[1/√2]^3+7/√2

= {13 /√2}/{1/2√2-1/√2+7/√2}=

{13/√2}/{1-2+14}/{2√2}

= 2

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