SSC CPO SI and ASI Model Paper 9

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Question : 136 of 200

Marks: +1, -0

If

a/b= 3 /4

and

b/c= 7/ 8

; then,

{a +b} /{b +c}=?

$49/60$
$7/30$
$32/ 3$
$49 /30$

Solution:

(1)

a /b=3/4 and b /c=7/8

4a = 3b and 8b = 7c

Substituting the values, we get,

∴32a/3 8b 7c

{a+b}/{b+c}={{24b}/ 32+b}/ b+8b /7

={24 +32}/32/{7+ 8}/7

$=56/32 × 7/15
=392 /480=49/ 60$

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