SSC CHSL Model Paper 19

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Question : 58 of 99

Marks: +1, -0

If

\sec θ = 13/5,

then

\tanθ - \sinθ + \cosθ

is equal to:

$121/65$
$118/65$
$23/13$
$124/65$

Solution:

\sec θ = 13/5

AB=√{13^2-5^2}

=√{169-25}=√144=12

\tanθ=12/5;\sinθ=12/13;

\cosθ=5/13

\tanθ - \sinθ + \cosθ=12/5-12/13+5/13

⇒

{156-60 + 25}/65=121/65

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