SSC CHSL Model Paper 19

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Question : 59 of 99

Marks: +1, -0

If

\sin 5θ =\cos (50° - 3θ),

then θ is equal to:

20°
25°
30°
15°

Solution:

\sin 5θ = \cos (50° - 3θ)

\cos(90° - 5θ) = cos(50° - 3θ)

⇒

90° - 5θ = 50° - 3θ

⇒

2θ = 40°

θ=40°/2=20°

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