SSC CHSL Model Paper 19

Question : 57 of 99

Marks: +1, -0

In ΔABC, P is a point on BC such that BP : PC = 1 : 2 and Q is the mid point of BP. Then, ar (ΔABQ) : ar (ΔABC) is equal to:

Solution:

BP : PC = 1 : 2

BP : BC = 1 : 3
BQ : BC =

1/2

: 3 = 1 : 6
ar(ΔABQ) : ar(ΔABC) = 1 : 6
(As altitude for both the triangles is same)

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