SSC CHSL Model Paper 11

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Question : 54 of 100

Marks: +1, -0

The value of

\sin^2 38° + \sin^2 52° + \sin^2 30° - \tan^2 45°

is equal to :

$1/3$
$1/4$
$3/4$
$1/2$

Solution:

\sin^2 38° + \sin^2 52°

+ \sin^2 30° - \tan^2 45°

= \sin^2 38° + \sin^2(90° - 38°)

+(1/2)^2-(1)^2

= \sin^2 38° + \cos^2 38° +1/4-1

=1+1/4-1=1/4

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