SSC CHSL Model Paper 11

In AABC,
∠ACB = 90°
∠BAC = 40°
∠ABC = 180° - (90° + 40°) = 180° - 130° = 50° ABCD is a cyclic quadrilateral
∠ADC = 180° - 50° = 130°
ABCD is a trapezium
AB || CD
∴ ∠ACD = 40°
∠CAD = 180° - (130° + 40°) = 180° - 170° = 10°