SSC CHSL Model Paper 11

Question : 55 of 100

Marks: +1, -0

ΔABC ~ ΔRQP and AB = 4 cm, BC = 6 cm and AC = 5 cm. If ar (ΔABC) : ar (ΔPQR) = 9 : 4, then PQ is equal to:

Solution:

ΔABC ~ ΔRQP

\text"ar (ΔABC)"/\text"ar (ΔPQR)"=(\BC)^2/(\PQ)^2

⇒9/4=6^2/(\PQ)^2

⇒\PQ^2={36×4}/9=4^2

⇒ \PQ= 4

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