SSC CHSL 7 Mar 2018 Shift 3 Paper

Section: English Language

Question : 9 of 100

Marks: +1, -0

In an alloy, aluminium and tin are in the ratio of 4 : 5. In the second alloy, the ratio of same elements is 4 : 7. If equal quantities of these two alloys be mixed to form a new alloy, then what will be the ratio of both of these elements in the new alloy?

2 : 3
16 : 35
4 : 5
40 : 59

Validate

Solution:

Ratio of aluminium and tin in first alloy = 4 : 5
Ratio of aluminium and tin in second alloy = 4 : 7
Let quantity of both alloys taken = L.C.M. (9,11) = 99 units
⇒ Aluminium in first alloy =

4/(4+5)×99=44

units
Tin present in first alloy =

99-44=55

units
Similarly, aluminium in second alloy = 36 units and tin = 63 units
∴ Ratio of aluminium and tin in the new alloy =

(44+36)/(55+63)

80/118=40/59

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