SSC CHSL 7 Mar 2018 Shift 3 Paper

Let weight of each bag be $\mathit{a},\mathit{b},\mathit{c}$ and 22 kg
Average weight of last three bags = 18 kg
⇒ $\mathit{b}+\mathit{c}+22=18\times 3$
⇒ $\mathit{b}+\mathit{c}=54-22=32$ -------------(i)
Also, average weight of first three bags = 19 kg
⇒ $\mathit{a}+\mathit{b}+\mathit{c}=19\times 3=57$
Substituting value from equation (i), ⇒ $\mathit{a}+32=57$
⇒ $\mathit{a}=57-32=25$kg