SSC CHSL 12 Aug 2021 Shift 3 Paper

According to the pie-chart (1);
Number of candidates enrolled from
$\mathit{P}=\frac{20}{100}\times 5500=1100$
Number of candidates enrolled from
$\mathit{Q}=\frac{30}{100}\times 5500=1650$
Number of candidates enrolled from
$\mathit{R}=\frac{12}{100}\times 5500=660$
Number of candidates enrolled from
$\mathit{S}=\frac{18}{100}\times 5500=990$
Number of candidates enrolled from
$\mathit{T}=\frac{20}{100}\times 5500=1100$
Now, according to the pie-chart (2)
Number of candidates passed from
$\mathit{P}=\frac{18}{100}\times 3300=594$
Number of candidates passed from
$\mathit{Q}=\frac{24}{100}\times 3300=792$
Number of candidates passed from
$\mathit{R}=\frac{18}{100}\times 3300=594$
Number of candidates passed from
$\mathit{S}=\frac{24}{100}\times 3300=792$
Number of candidates passed from
$\mathit{T}=\frac{16}{100}\times 3300=528$
$\therefore$ Required per cent of
$\mathit{P}=\frac{594}{1100}\times 100=54\%$
Required per cent of
$\mathit{Q}=\frac{792}{1650}\times 100=48\%$
Required per cent of
$\mathit{R}=\frac{594}{660}\times 100=90\%$
Required per cent of
$\mathit{S}=\frac{792}{990}\times 100=80\%$
Required per cent of
$\mathit{T}=\frac{528}{1100}\times 100=48\%$
Hence, per cent is highest in Institute R.