SSC CHSL 12 Aug 2021 Shift 3 Paper

Section: Quantitative Aptitude

Question : 60 of 99

Marks: +1, -0

A car takes

50 {min}

to cover a certain distance at a speed of

54 {km} \/ {h}

. If the speed is increased by

25 \%

, then how long will it take to cover three-fourth of the same distance?

Solution:

Given, speed

=54 {km} \/ {h}

= \;\; \;{54}/{60} {km} \/ {min}=\;{9}/{10} {km} \/ {min}

\;\text " Time "\; \;\; =50 {min}

∴ \;\text " Distance "\; \;\; =\;\text " speed "\; × \;\text " time "\;

\;\; =\;{9}/{10} × 50=45 {km}

Now, according to the question,
New time taken

\;\; =\;{\;\text " Distance "\;}/{\;\text " Speed "\;}

\;\; =\;{3 × 45 × 10}/{4 × 9 × 125}=30 {min}

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