SSC CGL 5 Aug 2017 Shift 1 Paper

Question : 66 of 100

Marks: +1, -0

Two circles of same radius intersect each other at P and Q. If the length of the common chord is 30 cm and distance between the centres of the two circles is 40 cm, then what is the radius (in cm) of the circles?

25
$25√2$
50
$50√2$

Validate

Solution:

According to the question,

PQ = 30 cm
∴

\PR=\PQ/2=30/2=15\cm

∵

OO'=40\cm

⇒

\OR=\OO'/2=40/2=20\cm

In ΔOPR,
∴

OP=√{(OR)^2 +(PR)^2}

=√{(20)^2+(15)^2}

=√{400+225}

=√625=25\cm

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