SSC CGL 5 Aug 2017 Shift 1 Paper

Question : 65 of 100

Marks: +1, -0

In the triangle ABC,∠BAC =50° and the bisectors of ∠ABC and ∠ACB meets at P. What is the value (in degree) of ∠BPC?

Solution:

According to the question,

∠BAC = 50°
∠BPC

= 90° + ∠\A/2=90°+50°/2

= 90°+ 25° = 115°

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