SSC CGL 12 Jun 2019 Shift 1 Paper

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Question : 74 of 100

Marks: +1, -0

If

\tan 4 \θ=\cot \ (40°-2 \θ\ ),

then

\θ

is equal to:

20°
25°
35°
30°

Solution:

\tan 4 \θ=\tan (90-40+2 \θ)

4 \θ=50+2 \θ

2 \θ=50

\θ=25°

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