SSC CGL 12 Jun 2019 Shift 1 Paper

Question : 73 of 100

Marks: +1, -0

The radii of the two circular faces of the frustum of a cone of height 21 cm are 5 cm and 3 cm. What is its volume in cm

^3

(\π = 22/7)

Solution:

h = 21
R = 5
r = 3

Volume

=\ {1}/{3} \π\ (\ {R}^{2}+\ {r}^{2}+\ {rR}\ ) \ {h}

=\ {1}/{3} \×\ {22}/{7} \×(25+9+15) \×21

=22 \×49=1078 \ {\cm}^{3}

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