Sainik School Entrance Exam 2019 Solved Paper

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Question : 38 of 150

Marks: +1, -0

A cube of side

4 {\cm}

contains a sphere touching its side. Then the volume of the gap in between is

30 cu. cm
30.48 cu. cm
30.84 cu. cm
31 cu. cm

Solution:

(b) Diameter of sphere

=

Side of cube

=4 {\cm}

So, radius of sphere

=2 {\cm}

Volume of the gap

=

Volume of cube

-

Volume of sphere

=a^3-{4}/{3} πr^3

=(4)^3-{4}/{3}×{22}/{7} ×(2)^3

=64-33.52=30.48 {\cm}^3.

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