Sainik School Entrance Exam 2019 Solved Paper

Question : 37 of 150

Marks: +1, -0

The total surface area of a cone having its slant height 9

{\dm}

and diameter of its base as

24 {\dm}

Solution:

(a) Total surface area of cone

=πr(r+l)

=22/7×(24/2)(24/2+9)

= 22/7×1221=792 \sq. \dm.

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