Sainik School Entrance Exam 2019 Solved Paper

Question : 39 of 150

Marks: +1, -0

A chord of a circle is of length

6 {\cm}

and it is at a distance of

4 {\cm}

from the centre. Find the radius of the circle

Solution:

By Pythagorus theorem,

r^2=OX^2+XQ^2

r^2= (4)^2+(3)^2

r^2=16+9

r^2=25

r=5\cm.

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