Trigonometry Practice Test 2

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Question : 11 of 22

Marks: +1, -0

The value of

\sin^2{2π}/15-\sin^2π/30

is:

${√5-1}/4$
${√5-1}/8$
${(√5+1)√3}/2$
${(√5-1)√3}/2$

Solution:

\sin^2{2π}/15-\sin^2π/30

=\sin ({2π}/15+π/30)\sin({2π}/15-π/30)

=\sinπ/6 . \sinπ/10=1/2×{√5-1}/4

={√5-1}/8

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