Trigonometry Practice Test 2

Question : 10 of 22

Marks: +1, -0

The moon's distance from the earth is 3,50,000 kilometres and its diameter subtends an angle of 31' at the eye of the observer. The diameter of the moon is:

$3157 (11/27)$ km
$315 (11/27)$ km
$3050 (11/27)$ km
None of these

Validate

Solution:

Let l be the diameter of moon and a its distance from the earth. If the moon subtends an angle θ at the eye of the observer, then

l=aθ=350000×(31/60×π/180)

=3157 (11/27)

Go to Question:

Prev Question

Next Question