Surds and Indices Practice Test 1

© examsiri.com

Question : 19 of 40

Marks: +1, -0

The value of

{(243)^0.13×(243)^{0.07}}/{(7)^{0.25}×(49)^0.075×(343)^0.2}

is:

$2 2/ 7$
$1 3/ 7$
$7 /3$
$3 / 7$

Solution:

{(243)^0.13×(243)^{0.07}}/{(7)^{0.25}×(49)^0.075×(343)^0.2}

={(3^5)^0.13×(3^5)^{0.07}}/{(7)^{0.25}×(7^2)^0.075×(7^3)^0.2}

={(3)^{0.65}×(3^0.35)}/{(7)^0.25×(7)^0.15×(7)^0.6}

=3^1/7^1=3/7

© examsiri.com

Go to Question:

Prev Question

Next Question