{(243)^{n/5}\times3^{2n+1}}/{9^n\times3^{n-1}}=?

Surds and Indices Practice Test 1

Question : 18 of 40

Marks: +1, -0

{(243)^{n/5}×3^{2n+1}}/{9^n×3^{n-1}}=?

Solution:

{{(243)^{n/5}× 3^{2n+1}}/{9^n×3^{n-1}}

={(3^5)^{n/5}× 3^{2n+1}}/{3^{2n}×3^{n-1}}

={(3 )^{n }× 3^{2n+1}}/{3^{2n}×3^{n-1}} =3^2=9

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