Surds and Indices Practice Test 1

Question : 20 of 40

Marks: +1, -0

10^ 0.48 =x

10^0.70 = y

and

x^z = y^2

, then what is the approximate value of z?

Solution:

x = 10^0.48, y = 10^0.70

x^z = y^2

⇒ (10^0.48)^z = (10^0.70)^2

⇒ 10^{0.48z} = 10^1.40

∴z=1.40/0.48=140/48=2.9

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