Indian Institute of Foreign Trade 2011 Solved Paper

Question : 51 of 120

Marks: +1, -0

Find the value of x from the following equation:

\log_{10}3+\log_{10}(4x+1)=\log_{10}(x+1)+1

Solution:

\log_{10}3+\log_{10}(4x+1)\log_{10}(x+1)+1

can be written as

\log_{10}3+\log_{10}(4x+1)=\log_{10}(x+1)+\log_{10}10

We know that

\log_{10}a+\log_{10}b=\log_{10}ab

\log_{10}3×(4x+1)=\log_{10}(x+1)×10

12x+3=10x+10

x = 7/2. Hence, option B is the correct answer

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