Indian Institute of Foreign Trade 2011 Solved Paper

i. Volume of the parallelepiped of length 5 cm, breadth 3 cm and height 4 cm$=3\times 4\times 5=60\mathit{c}{\mathit{m}}^3$
ii. Volume of the cube of each side 4 cm $4^3=64\mathit{c}{\mathit{m}}^3$
iii.Volume of the cylinder of radius 3 cm and length 3 cm $=\mathit{\pi }\times 3^2\times 3=84.82\mathit{c}{\mathit{m}}^2$
iv. Volume of the sphere of radius 3 cm $=\frac{4}{3}\times \mathit{\pi }\times 3^3=113.09\mathit{c}{\mathit{m}}^2$
Therefore, we can say that volumes of the objects in decreasing order = iv,iii,ii,i.
Hence, option A is the correct answer.