Indian Institute of Foreign Trade 2011 Solved Paper

When the paper is rolled along its length, the circumference of the cylinder formed is equal to the length and the height is equal to the breadth of the rectangle.
Let 'r' be the radius and 'h' be the height of the cylinder formed.
$2\mathit{\pi }\times \mathit{r}=22$ and $\mathit{h}=10$
Hence, the volume of the cylinder $={\mathit{\pi }}^2\times {\mathit{r}}^2\times \mathit{h}=\frac{22}{7}{\left(\frac{7}{2}\right)}^2\times 10=385{\mathrm{cm}}^2$