IBPS SO Prelims Exam Model Paper 5

I. x2 – 18x + 80 = 0
⇒ x2 – 10x – 8x + 80 = 0
⇒ x(x – 10) – 8(x – 10) = 0
⇒ (x – 10) (x – 8) = 0
⇒ x = 10, 8
II. y2 – 16y + 63 = 0
⇒ y2 – 9y – 7y + 63 = 0
⇒ y(y – 9) – 7(y – 9) = 0
⇒ (y – 9) (y – 7) = 0
⇒ y = 9, 7Hence the relationship between x and y cannot be established.