IBPS SO Prelims Exam Model Paper 5

I. 3x2 – 10x + 3 = 0
⇒ 3x2 – 9x – x + 3 = 0
⇒ 3x(x – 3) – 1 (x – 3) = 0
⇒ (x – 3) (3x – 1) = 0
⇒ x = 3,

1

3

II. 18y2 – 9y + 1 = 0
⇒ 18y2 – 6y – 3y + 1 = 0
⇒ 6y(3y – 1) – 1(3y – 1) = 0
⇒ (3y – 1) (6y – 1) = 0
⇒ y =

1

3

,

1

6

Hence, x ≥ y